GregorianToJD
You can get todays day time and date using this code
<?php
echo date("d")." ";
echo date("m")." ";
echo date("Y")." ";
echo date("h:i:s A");
ECHO ' <br/>';
echo jddayofweek ( cal_to_jd(CAL_GREGORIAN, date("m"),date("d"), date("Y")) , 1 );
?>
JDDayOfWeek
(PHP 4, PHP 5)
JDDayOfWeek — Returns the day of the week
Description
Returns the day of the week. Can return a string or an integer depending on the mode.
Parameters
- julianday
-
A julian day number as integer
- mode
-
Calendar week modes Mode Meaning 0 (Default) Return the day number as an int (0=Sunday, 1=Monday, etc) 1 Returns string containing the day of week (English-Gregorian) 2 Return a string containing the abbreviated day of week (English-Gregorian)
Return Values
The gregorian weekday as either an integer or string.
add a note
User Contributed NotesJDDayOfWeek
nrkkalyan at rediffmail dot com
26-Feb-2005 07:08
26-Feb-2005 07:08
php at xtramicro dot com
07-Sep-2004 05:28
07-Sep-2004 05:28
Be aware that date() and mktime() only work as long as you move within the UNIX era (1970 - 2038 / 0x0 - 0x7FFFFFFF in seconds). Outside that era those functions are only generating errors.
In other words: mktime(0, 0, 0, 12, 31, 1969) *DOES NOT* work (and so doesn't date() fed with with mktime()'s result from above). But cal_to_jd(CAL_GREGORIAN, 12, 11, 1969) *DOES WORK*.
And please note that the calendar-extension's functions arguments follow the US date order: month - day - year.